Calculating the Mass of Oxygen Produced from Sodium Chlorate

Oct 13, 2025 by recoveryshake.com 37 views

Calculating the Mass of Oxygen Produced from Sodium Chlorate

Understanding the Chemical Reaction

The given reaction is a decomposition reaction where sodium chlorate (NaClO3) breaks down into sodium chloride (NaCl) and oxygen gas (O2). This reaction is often used in the production of oxygen gas. To calculate the mass of oxygen produced from 12.00 moles of sodium chlorate, we need to understand the stoichiometry of the reaction.

Balanced Chemical Equation

The balanced chemical equation for the reaction is:

2 NaClO3(s) → 2 NaCl(s) + 3 O2(g)

From the equation, we can see that 2 moles of sodium chlorate produce 3 moles of oxygen gas. This is the key to calculating the mass of oxygen produced.

Molar Mass of Sodium Chlorate and Oxygen

To calculate the mass of oxygen produced, we need to know the molar mass of sodium chlorate and oxygen. The molar mass of sodium chlorate (NaClO3) is:

22.99 g/mol (Na) + 35.45 g/mol (Cl) + 3(16.00 g/mol) (O) = 106.44 g/mol

The molar mass of oxygen (O2) is:

2(16.00 g/mol) = 32.00 g/mol

Calculating the Mass of Oxygen Produced

Now that we have the molar mass of sodium chlorate and oxygen, we can calculate the mass of oxygen produced from 12.00 moles of sodium chlorate. We can use the mole ratio from the balanced equation to calculate the number of moles of oxygen produced:

2 moles NaClO3 → 3 moles O2

So, for 12.00 moles of NaClO3, we can calculate the number of moles of O2 produced as follows:

moles O2 = (3/2) × moles NaClO3 = (3/2) × 12.00 mol = 18.00 mol

Now that we have the number of moles of oxygen produced, we can calculate the mass of oxygen produced using the molar mass of oxygen:

mass O2 = moles O2 × molar mass O2 = 18.00 mol × 32.00 g/mol = 576.00 g

Therefore, 12.00 moles of sodium chlorate will produce 576.00 grams of oxygen gas.

Conclusion

In this article, we calculated the mass of oxygen produced from 12.00 moles of sodium chlorate using the balanced chemical equation and the molar masses of sodium chlorate and oxygen. We used the mole ratio from the balanced equation to calculate the number of moles of oxygen produced and then calculated the mass of oxygen produced using the molar mass of oxygen. The result shows that 12.00 moles of sodium chlorate will produce 576.00 grams of oxygen gas.

References

Chemistry: An Atoms First Approach, by Steven S. Zumdahl
General Chemistry: Principles and Modern Applications, by Linus Pauling

Additional Information

Sodium chlorate is a strong oxidizing agent and can be used in the production of oxygen gas.
The reaction is often used in the production of oxygen gas for industrial and medical applications.
The molar mass of sodium chlorate and oxygen can be calculated using the atomic masses of the elements involved.
Frequently Asked Questions: Calculating the Mass of Oxygen Produced from Sodium Chlorate

Q: What is the balanced chemical equation for the reaction between sodium chlorate and oxygen?

A: The balanced chemical equation for the reaction is:

2 NaClO3(s) → 2 NaCl(s) + 3 O2(g)

Q: How many moles of oxygen are produced from 12.00 moles of sodium chlorate?

A: Using the mole ratio from the balanced equation, we can calculate the number of moles of oxygen produced as follows:

moles O2 = (3/2) × moles NaClO3 = (3/2) × 12.00 mol = 18.00 mol

Q: What is the molar mass of oxygen?

A: The molar mass of oxygen (O2) is:

2(16.00 g/mol) = 32.00 g/mol

Q: How can I calculate the mass of oxygen produced from 12.00 moles of sodium chlorate?

A: To calculate the mass of oxygen produced, we can use the number of moles of oxygen produced and the molar mass of oxygen:

mass O2 = moles O2 × molar mass O2 = 18.00 mol × 32.00 g/mol = 576.00 g

Q: What is the significance of the mole ratio in the balanced equation?

A: The mole ratio in the balanced equation indicates the ratio of moles of reactants to moles of products. In this case, 2 moles of sodium chlorate produce 3 moles of oxygen gas. This ratio is used to calculate the number of moles of oxygen produced from a given amount of sodium chlorate.

Q: Can I use this method to calculate the mass of oxygen produced from any amount of sodium chlorate?

A: Yes, you can use this method to calculate the mass of oxygen produced from any amount of sodium chlorate by following the same steps:

Calculate the number of moles of oxygen produced using the mole ratio from the balanced equation.
Calculate the mass of oxygen produced using the number of moles of oxygen and the molar mass of oxygen.

Q: What are some common applications of the reaction between sodium chlorate and oxygen?

A: The reaction between sodium chlorate and oxygen is often used in the production of oxygen gas for industrial and medical applications. Some common applications include:

Oxygen therapy for patients with respiratory problems
Industrial processes that require oxygen, such as steel production and chemical synthesis
Medical procedures that require oxygen, such as surgery and anesthesia

Q: Can I use this method to calculate the mass of oxygen produced from other compounds that decompose into oxygen?

A: Yes, you can use this method to calculate the mass of oxygen produced from other compounds that decompose into oxygen by following the same steps:

Write the balanced chemical equation for the reaction.
Calculate the mole ratio of the reactants to the products.
Calculate the number of moles of oxygen produced using the mole ratio.
Calculate the mass of oxygen produced using the number of moles of oxygen and the molar mass of oxygen.

Note: The specific steps may vary depending on the compound and the reaction.