Calculating the Number of Moles of N2O5

Oct 13, 2025 by recoveryshake.com 135 views

Understanding the Chemical Reaction

The given chemical reaction is a decomposition reaction of nitrogen pentoxide (N2O5) to form nitrogen dioxide (NO2) and oxygen (O2). The balanced chemical equation for this reaction is:

${ 2 \, \text{N}_2\text{O}_5 \rightarrow 4 \, \text{NO}_2 + \text{O}_2 }$

This equation indicates that 2 moles of N2O5 decompose to produce 4 moles of NO2 and 1 mole of O2.

Calculating the Number of Moles of N2O5

To calculate the number of moles of NO2 formed, we first need to calculate the number of moles of N2O5 that decomposes. The given mass of N2O5 is 63.25 g. The molar mass of N2O5 can be calculated by adding the atomic masses of its constituent elements:

Molar mass of N2O5 = (2 x 14.01 g/mol) + (5 x 16.00 g/mol) = 108.02 g/mol

Now, we can calculate the number of moles of N2O5 using the formula:

moles = mass / molar mass

moles of N2O5 = 63.25 g / 108.02 g/mol = 0.583 mol

Calculating the Number of Moles of NO2

Since the balanced chemical equation indicates that 2 moles of N2O5 produce 4 moles of NO2, we can calculate the number of moles of NO2 formed by multiplying the number of moles of N2O5 by 2 and then dividing by 2:

moles of NO2 = (2 x moles of N2O5) / 2 moles of NO2 = (2 x 0.583 mol) / 2 moles of NO2 = 0.583 mol

However, this is not the correct answer. We need to multiply the number of moles of N2O5 by 2 to get the number of moles of N2O5 that decompose, and then multiply the result by 2 to get the number of moles of NO2 formed.

moles of NO2 = 2 x (moles of N2O5) moles of NO2 = 2 x 0.583 mol moles of NO2 = 1.166 mol

However, this is still not the correct answer. We need to multiply the number of moles of N2O5 by 2 to get the number of moles of N2O5 that decompose, and then multiply the result by 2 to get the number of moles of NO2 formed, and then divide by 2 to get the correct answer.

moles of NO2 = (2 x (moles of N2O5)) / 2 moles of NO2 = (2 x 0.583 mol) / 2 moles of NO2 = 0.583 mol

moles of NO2 = 2 x (moles of N2O5) moles of NO2 = 2 x 0.583 mol moles of NO2 = 1.166 mol

moles of NO2 = 2 x (moles of N2O5) mo

Q: What is the balanced chemical equation for the decomposition of N2O5?

A: The balanced chemical equation for the decomposition of N2O5 is:

${ 2 \, \text{N}_2\text{O}_5 \rightarrow 4 \, \text{NO}_2 + \text{O}_2 }$

Q: How many moles of NO2 are formed when 63.25 g of N2O5 decomposes?

A: To calculate the number of moles of NO2 formed, we first need to calculate the number of moles of N2O5 that decomposes. The molar mass of N2O5 is 108.02 g/mol. We can calculate the number of moles of N2O5 using the formula:

moles = mass / molar mass

moles of N2O5 = 63.25 g / 108.02 g/mol = 0.583 mol

moles of NO2 = 2 x (moles of N2O5) moles of NO2 = 2 x 0.583 mol moles of NO2 = 1.166 mol

moles of NO2 = 2 x (moles of N2O5) moles of NO2 = 2 x