Introduction to Solving Systems by Elimination

Oct 13, 2025 by recoveryshake.com 48 views

Introduction to Solving Systems by Elimination

Solving systems of linear equations by elimination is a powerful technique used to find the solution to a system of equations. This method involves adding or subtracting equations to eliminate one of the variables, making it easier to solve for the other variable. In this article, we will practice solving systems of linear equations by elimination and provide a step-by-step explanation of the process.

Step 1: Write Down the System of Equations

To solve a system of linear equations by elimination, we need to start by writing down the system of equations. Let's consider the following system of equations:

${$ \left{\begin{array}{l}-x + y = 5 \ x - 5y = -9\end{array}\right.$}$

Step 2: Multiply the Equations by Necessary Multiples

To eliminate one of the variables, we need to multiply the equations by necessary multiples such that the coefficients of the variable to be eliminated are the same. Let's multiply the first equation by 1 and the second equation by 1.

${$ \left{\begin{array}{l}-x + y = 5 \ x - 5y = -9\end{array}\right.$}$

Step 3: Add or Subtract the Equations

Now that we have the equations multiplied by necessary multiples, we can add or subtract the equations to eliminate one of the variables. Let's add the two equations to eliminate the variable x.

${-x + y = 5}$ ${x - 5y = -9}$

Adding the two equations, we get:

${-6y = -4}$

Step 4: Solve for the Variable

Now that we have eliminated the variable x, we can solve for the variable y. Let's solve for y by dividing both sides of the equation by -6.

${-6y = -4}$ ${y = \frac{-4}{-6}}$ ${y = \frac{2}{3}}$

Step 5: Substitute the Value of the Variable into One of the Original Equations

Now that we have the value of the variable y, we can substitute it into one of the original equations to solve for the other variable. Let's substitute the value of y into the first equation.

${-x + y = 5}$ ${-x + \frac{2}{3} = 5}$

Step 6: Solve for the Other Variable

Now that we have the value of the variable y substituted into one of the original equations, we can solve for the other variable x. Let's solve for x by isolating x on one side of the equation.

${-x + \frac{2}{3} = 5}$ ${-x = 5 - \frac{2}{3}}$ ${-x = \frac{13}{3}}$ ${x = -\frac{13}{3}}$

Conclusion

In this article, we practiced solving a system of linear equations by elimination. We started by writing down the system of equations, multiplied the equations by necessary multiples, added or subtracted the equations to eliminate one of the variables, solved for the variable, substituted the value of the variable into one of the original equations, and solved for the other variable. By following these steps, we were able to find the solution to the system of equations.

Practice Problems

Now that we have practiced solving a system of linear equations by elimination, let's try solving another system of equations using the same technique.

Problem 1

${$ \left{\begin{array}{l}2x + 5y = -24 \ 3x - 5y = 7\end{array}\right.$}$

Problem 2

${$ \left{\begin{array}{l}x + 2y = 7 \ 2x - 3y = -2\end{array}\right.$}$

Problem 3

${$ \left{\begin{array}{l}3x + 2y = 14 \ x - 2y = -3\end{array}\right.$}$

Discussion

Solving systems of linear equations by elimination is a powerful technique used to find the solution to a system of equations. By following the steps outlined in this article, we can solve systems of linear equations by elimination. However, it's worth noting that this technique may not always be the most efficient way to solve a system of equations, and other techniques such as substitution or graphing may be more suitable in certain situations.

References

[1] "Solving Systems of Linear Equations" by Math Open Reference
[2] "Solving Systems of Linear Equations by Elimination" by Khan Academy
[3] "Solving Systems of Linear Equations" by Purplemath

Conclusion

Q: What is the elimination method in solving systems of linear equations?

A: The elimination method is a technique used to solve systems of linear equations by adding or subtracting equations to eliminate one of the variables, making it easier to solve for the other variable.

Q: How do I choose which variable to eliminate?

A: To choose which variable to eliminate, you need to look at the coefficients of the variables in the two equations. If the coefficients of the same variable are the same, you can eliminate that variable by adding or subtracting the equations. If the coefficients are not the same, you need to multiply one or both of the equations by a necessary multiple to make the coefficients the same.

Q: What is the difference between the elimination method and the substitution method?

A: The elimination method and the substitution method are two different techniques used to solve systems of linear equations. The elimination method involves adding or subtracting equations to eliminate one of the variables, while the substitution method involves solving one equation for one variable and substituting that expression into the other equation.

Q: Can I use the elimination method to solve a system of three or more equations?

A: Yes, you can use the elimination method to solve a system of three or more equations. However, it may be more complicated and require more steps. You need to eliminate one variable at a time, and then use the resulting equation to eliminate another variable.

Q: What if I get a contradiction when using the elimination method?

A: If you get a contradiction when using the elimination method, it means that the system of equations has no solution. This can happen if the equations are inconsistent, meaning that they cannot be true at the same time.

Q: Can I use the elimination method to solve a system of equations with fractions?

A: Yes, you can use the elimination method to solve a system of equations with fractions. However, you need to be careful when multiplying or dividing fractions to avoid getting incorrect results.

Q: What are some common mistakes to avoid when using the elimination method?

A: Some common mistakes to avoid when using the elimination method include:

Not multiplying or dividing fractions correctly
Not checking for contradictions
Not following the order of operations
Not using the correct method for solving the system of equations

Q: How do I know if the elimination method is the best method to use for a particular system of equations?

A: To determine if the elimination method is the best method to use for a particular system of equations, you need to consider the following factors:

The complexity of the equations
The number of variables
The type of coefficients (e.g. integers, fractions, decimals)
The type of solution (e.g. exact, approximate)

If the system of equations is simple and has a small number of variables, the elimination method may be the best method to use. However, if the system of equations is complex or has a large number of variables, the substitution method or graphing method may be more suitable.

Q: Can I use the elimination method to solve a system of equations with decimals?

A: Yes, you can use the elimination method to solve a system of equations with decimals. However, you need to be careful when multiplying or dividing decimals to avoid getting incorrect results.

Q: What are some real-world applications of the elimination method?

A: The elimination method has many real-world applications, including:

Solving systems of linear equations in physics and engineering
Finding the intersection of two or more lines in geometry
Solving systems of linear equations in economics and finance
Finding the solution to a system of linear equations in computer science

Conclusion

In conclusion, the elimination method is a powerful technique used to solve systems of linear equations. By following the steps outlined in this article, you can use the elimination method to solve systems of linear equations and understand the underlying concepts. We hope this Q&A article has been helpful in answering your questions and providing a better understanding of the elimination method.