Simplifying the Exponent of the Binomial

Oct 13, 2025 by recoveryshake.com 87 views

Understanding the Problem

To simplify the given expression, we need to apply the rules of exponents and multiplication. The expression is $\left(-2 x^3\right)^2 \cdot y \cdot y^9$ . We will start by simplifying the exponent of the binomial $-2 x^3$ .

Simplifying the Exponent of the Binomial

When we have a binomial raised to a power, we need to apply the power to each term inside the binomial. In this case, we have $\left(-2 x^3\right)^2$ . Using the power rule of exponents, we can rewrite this as $(-2)^2 \cdot (x^3)^2$ .

Applying the Power Rule of Exponents

The power rule of exponents states that for any numbers $a$ and $b$ and any integer $n$ , $(ab)^n = a^n \cdot b^n$ . We can apply this rule to simplify the expression $(-2)^2 \cdot (x^3)^2$ . This gives us $4 \cdot x^{3 \cdot 2}$ .

Simplifying the Expression

Using the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ , we can simplify the expression $4 \cdot x^{3 \cdot 2}$ to $4 \cdot x^6$ .

Multiplying the Terms

Now that we have simplified the exponent of the binomial, we can multiply the terms together. We have $4 \cdot x^6 \cdot y \cdot y^9$ . Using the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ , we can simplify this expression to $4 \cdot x^6 \cdot y^{1+9}$ .

Simplifying the Exponent of y

Using the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ , we can simplify the expression $y^{1+9}$ to $y^{10}$ .

Combining the Terms

Now that we have simplified the exponent of y, we can combine the terms together. We have $4 \cdot x^6 \cdot y^{10}$ . This is the simplified form of the original expression.

Conclusion

In conclusion, the simplified form of the expression $\left(-2 x^3\right)^2 \cdot y \cdot y^9$ is $4 \cdot x^6 \cdot y^{10}$ , which can be written as $4 x^6 y^{10}$ .

Final Answer

The final answer is $\boxed{4 x^6 y^{10}}$ .

Frequently Asked Questions

Q: What is the simplified form of the expression $\left(-2 x^3\right)^2 \cdot y \cdot y^9$ ?

A: The simplified form of the expression $\left(-2 x^3\right)^2 \cdot y \cdot y^9$ is $4 x^6 y^{10}$ .

Q: How do I simplify the exponent of the binomial $-2 x^3$ ?

A: To simplify the exponent of the binomial $-2 x^3$ , you need to apply the power to each term inside the binomial. Using the power rule of exponents, you can rewrite this as $(-2)^2 \cdot (x^3)^2$ .

Q: What is the power rule of exponents?

A: The power rule of exponents states that for any numbers $a$ and $b$ and any integer $n$ , $(ab)^n = a^n \cdot b^n$ . This means that when you have a binomial raised to a power, you need to apply the power to each term inside the binomial.

Q: How do I simplify the expression $(-2)^2 \cdot (x^3)^2$ ?

A: Using the power rule of exponents, you can simplify the expression $(-2)^2 \cdot (x^3)^2$ to $4 \cdot x^{3 \cdot 2}$ .

Q: What is the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ ?

A: The rule of exponents that states $x^m \cdot x^n = x^{m+n}$ means that when you multiply two terms with the same base, you can add their exponents.

Q: How do I simplify the expression $4 \cdot x^{3 \cdot 2}$ ?

A: Using the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ , you can simplify the expression $4 \cdot x^{3 \cdot 2}$ to $4 \cdot x^6$ .

Q: What is the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ ?

A: The rule of exponents that states $x^m \cdot x^n = x^{m+n}$ means that when you multiply two terms with the same base, you can add their exponents.

Q: How do I simplify the expression $4 \cdot x^6 \cdot y \cdot y^9$ ?

A: Using the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ , you can simplify the expression $4 \cdot x^6 \cdot y \cdot y^9$ to $4 \cdot x^6 \cdot y^{1+9}$ .

Q: What is the simplified form of the expression $4 \cdot x^6 \cdot y^{1+9}$ ?

A: Using the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ , you can simplify the expression $4 \cdot x^6 \cdot y^{1+9}$ to $4 \cdot x^6 \cdot y^{10}$ .

Q: What is the final answer?

A: The final answer is $\boxed{4 x^6 y^{10}}$ .

Additional Resources

For more information on simplifying expressions with exponents, see the article on Simplifying Expressions with Exponents.
For more information on the power rule of exponents, see the article on Power Rule of Exponents.
For more information on the rule of exponents that states $x^m \cdot x^n = x^{m+n}$ , see the article on Rule of Exponents.

Conclusion

In conclusion, the simplified form of the expression $\left(-2 x^3\right)^2 \cdot y \cdot y^9$ is $4 x^6 y^{10}$ . We hope this Q&A article has been helpful in understanding the steps involved in simplifying the expression. If you have any further questions, please don't hesitate to ask.